2x-[3-z-(1-z)]=6

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Solution for 2x-[3-z-(1-z)]=6 equation:


Simplifying
2x + -1[3 + -1z + -1(1 + -1z)] = 6
2x + -1[3 + -1z + (1 * -1 + -1z * -1)] = 6
2x + -1[3 + -1z + (-1 + 1z)] = 6

Reorder the terms:
2x + -1[3 + -1 + -1z + 1z] = 6

Combine like terms: 3 + -1 = 2
2x + -1[2 + -1z + 1z] = 6

Combine like terms: -1z + 1z = 0
2x + -1[2 + 0] = 6
2x + -1[2] = 6

Multiply -1 * 2
2x + -2 = 6

Reorder the terms:
-2 + 2x = 6

Solving
-2 + 2x = 6

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 2x = 6 + 2

Combine like terms: -2 + 2 = 0
0 + 2x = 6 + 2
2x = 6 + 2

Combine like terms: 6 + 2 = 8
2x = 8

Divide each side by '2'.
x = 4

Simplifying
x = 4

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